## Engage NY Eureka Math 4th Grade Module 3 Lesson 34 Answer Key

### Eureka Math Grade 4 Module 3 Lesson 34 Problem Set Answer Key

Question 1.

Use the associative property to rewrite each expression.

Solve using disks, and then complete the number sentences.

a. 30 × 24

= ( _3___ × 10) × 24

= __3__ × (10 × 24)

= ___720____

Answer:

30 X 24

= (3 X 10) X 24

= 3 X (10 X 24)

= 720,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 30 X 24

= (3 X 10) X 24

= 3 X (10 X 24)

= 720.

b. 40 × 43

= (4 × 10) × __43___

= 4 × (10 × _43__ )

= __1,720_____

Answer:

40 X 43

= (4 X 10) X 43

= 4 X (10 X43)

= 1,720,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 40 X 43

= (4 X 10) X 43

= 4 X (10 X43)

= 1,720.

c. 30 × 37

= (3 × _10___ ) × __37___

= 3 × (10 × __37___ )

= __1,110_____

Answer:

30 × 37

= (3 × 10) × 37

= 3 × (10 × 37)

= 1,110

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 30 × 37

= (3 × 10) × 37

= 3 × (10 × 37)

= 1,110

Question 2.

Use the associative property and place value disks to solve.

a. 20 × 27

Answer:

20 X 27

= (2 X 10) X 27

= 2 X (10 X 27)

= 540,

Explanation:

Used the associative property and placed value

disks to solve 20 X 27

= (2 X 10) X 27

= 2 X (10 X 27)

= 540 as shown above.

b. 40 × 31

Answer:

40 X 31

= (4 X 10) X 31

= 4 X (10 X 31)

= 1,240,

Explanation:

Used the associative property and placed value

disks to solve 40 X 31

= (4 X 10) X 31

= 4 X (10 X 31)

= 1,240 as shown above.

Question 3.

Use the associative property without place value disks to solve.

a. 40 × 34

Answer:

Explanation:

Used the associative property and placed value

disks to solve 40 X 34

= (4 X 10) X 34

= 4 X (10 X 34)

= 1,360

b. 50 × 43

Answer:

Explanation:

Used the associative property and placed value

disks to solve 50 X 43

= (5 X 10) X 43

= 5 X (10 X 43)

= 2,150

Question 4.

Use the distributive property to solve the following problems.

Distribute the second factor.

a. 40 × 34

Answer:

40 X 34

= (40 X 30 ) + (40 X 4)

= 1,200 + 160

= 1,360,

Explanation:

Used the distributive property and distribute the

second factor as 40 X 34

= (40 X 30 ) + (40 X 4)

= 1,200 + 160

= 1,360.

b. 60 × 25

Answer:

60 X 25

= (60 X 20) + (60 X 5)

= 1,200 + 300

= 1,500,

Explanation:

Used the distributive property and distribute the

second factor as 60 X 25

= (60 X 20) + (60 X 5)

= 1,200 + 300

= 1,500.

### Eureka Math Grade 4 Module 3 Lesson 34 Exit Ticket Answer Key

Question 1.

Use the associative property to rewrite each expression.

Solve using disks, and then complete the number sentences.

20 × 41

hundreds tens ones

_(2_ × _10)___ × _41___ = _820_

Answer:

20 X 41

= (2 X 10) X 41

= 2 X (10 X 41)

= 820,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 20 X 41

= (2 X 10) X 41

= 2 X (10 X 41)

= 820.

Question 2.

Distribute 32 as 30 + 2 and solve.

60 × 32

Answer:

= 60 X 32

= 60 X (30 + 2)

= (60 X 30) + (60 X 2)

= 1,800 + 120

= 1,920,

Explanation:

Distributed 32 as 30 + 2 and solved as

= 60 X 32

= 60 X (30 + 2)

= (60 X 30) + (60 X 2)

= 1,800 + 120

= 1,920.

### Eureka Math Grade 4 Module 3 Lesson 34 Homework Answer Key

Question 1.

Use the associative property to rewrite each expression.

Solve using disks, and then complete the number sentences.

a. 20 × 34

= (__2__ × 10) × 34

= __2__ × (10 × 34)

= ___680____

Answer:

20 X 34

= (2 X 10) X 34

= 2 X (10 X 34)

= 680,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 20 X 34

= (2 X 10) X 34

= 2 X (10 X 34)

= 680.

b. 30 × 34

= (3 × 10) × __34___

= 3 × (10 × _34__)

= __1,020_____

Answer:

30 X 34

= (2 X 10) X 34

= 3 X (10 X 34)

=1,020

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 30 X 34

= (3 X 10) X 34

= 3 X (10 X 34)

= 1,020

c. 30 × 42

= (3 × _10___) × _42____

= 3 × (10 × __42___)

= __1,260_____

Answer:

30 X 42

= (3 X 10) X 42

= 3 X (10 X 42)

= 1,260

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 30 X 42

= (3 X 10) X 42

= 3 X (10 X 42)

= 1,260

Question 2.

Use the associative property and place value disks to solve.

a. 20 × 16

Answer:

20 X 16

= (2 X 10) X 16

= 2 X (10 X 16)

= 320,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 20 X 16

= (2 X 10) X 16

= 2 X (10 X 16)

= 320.

b. 40 × 32

Answer:

40 X 32

= (4 X 10) X 32

= 4 X (10 X 32)

= 1,280,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 40 X 32

= (4 X 10) X 32

= 4 X (10 X 32)

= 1,280.

Question 3.

Use the associative property without place value disks to solve.

a. 30 × 21

Answer:

30 X 21

= (3 X 10) X 21

= 3 X (10 X 21)

= 630,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 30 X 21

= (3 X 10) X 21

= 3 X (10 X 21)

= 630.

b. 60 × 42

Answer:

60 X 42

= (6 X 10) X 42

= 6 X (10 X 42)

= 2,520,

Explanation:

Used the associative property to rewrite each expression.

Solved using disks, and then completed the number sentences

as 60 X 42

= (6 X 10) X 42

= 6 X (10 X 42)

= 2,520.

Question 4.

Use the distributive property to solve the following.

Distribute the second factor.

a. 40 × 43

Answer:

40 X 43

= (40 X 40) + (40 X 3)

= 1,600 + 120

= 1,720,

Explanation:

Used the distributive property and distribute the

second factor as 40 X 43

= (40 X 40) + (40 X 3)

= 1,600 + 120

= 1,720.

b. 70 × 23

Answer

= 70 X 23

= (70 X 20) + (70 X 3)

= 1,400 + 210

= 1,610,

Explanation:

Used the distributive property and distribute the

second factor as 60 X 25

= (70 X 20) + (70 X 3)

= 1,400 + 210

= 1,610.